Jaylen Warren wins AFC Offensive Player of the Week award

The Steelers got a big win against the Colts with Jaylen Warren leading the way.

He has now been named the AFC Offensive Player of the Week.

Warren finished with a new career high with 188 yards from scrimmage – 101 rushing and 87 receiving. He also had two touchdowns, one through the air and one on the ground.

The league notes that Warren became the sixth player in league history and the first in 40 seasons with a receiving touchdown of at least 80 yards and a rushing touchdown of at least 50 yards in the same game. Jim Brown, Gale Sayers, Harmon Wages, Herschel Walker and Delvin Williams are previous players to accomplish this feat.

This is Warren’s first Offensive Player of the Week award and he is the first Steelers player to earn the honor since Ben Roethlisberger in Week 10 of the 2020 season.

The Steelers will be on their way to face the Buccaneers in Week 6.

Gn sports

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